What is the solution for (dy}{dx}=\frac{x-1)/y ?

The solution for (dy}{dx}=\frac{x-1)/y is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}

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(dy}{dx}=\frac{x-1)/y

\frac{d y}{d x} = \frac{x - 1}{y}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x - 1}{y}

Solve separable ODE:

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

\int \frac{x ^{2}}{x ^{2} - 16} d x

\int \frac{1}{( a + b x ) ^{3}} d x

\int_{0}^{0.5} (300 x) d x

y^{^{''}} = 4 t^{3} + t

y = (x - 5) x (x + 5), y = 5 - x

What is the solution for (dy}{dx}=\frac{x-1)/y ?
The solution for (dy}{dx}=\frac{x-1)/y is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}