What is the derivative of (sqrt(3x-1)/((2-x)^2)) ?

The derivative of (sqrt(3x-1)/((2-x)^2)) is -(9x+2)/(2(x-2)^3sqrt(3x-1))

What is the first derivative of (sqrt(3x-1)/((2-x)^2)) ?

The first derivative of (sqrt(3x-1)/((2-x)^2)) is -(9x+2)/(2(x-2)^3sqrt(3x-1))

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\frac{d}{d x} (\frac{3 x - 1}{( 2 - x ) ^{2}})

- \frac{9 x + 2}{2 ( x - 2 ) ^{3} 3 x - 1}

Solution steps

\frac{d}{d x} (\frac{3 x - 1}{( 2 - x ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x - 1 ) ( 2 - x ) ^{2} - \frac{d}{d x} ( ( 2 - x ) ^{2} ) 3 x - 1}{( ( 2 - x ) ^{2} ) ^{2}}

\frac{d}{d x} (3 x - 1) = \frac{3}{2 3 x - 1}

\frac{d}{d x} ((2 - x)^{2}) = - 2 (2 - x)

= \frac{\frac{3}{2 3 x - 1} ( 2 - x ) ^{2} - ( - 2 ( 2 - x ) ) 3 x - 1}{( ( 2 - x ) ^{2} ) ^{2}}

Simplify

\frac{\frac{3}{2 3 x - 1} ( 2 - x ) ^{2} - ( - 2 ( 2 - x ) ) 3 x - 1}{( ( 2 - x ) ^{2} ) ^{2}} : - \frac{9 x + 2}{2 ( x - 2 ) ^{3} 3 x - 1}

= - \frac{9 x + 2}{2 ( x - 2 ) ^{3} 3 x - 1}

d x - 2 x y d y = 0

\frac{d}{d x} (\frac{( x - 1 ) ( x ^{2} + x + 1 )}{x ^{3}})

f (x) = 3 - 2 x + 4 x^{3}, at x = - 1

\int \frac{1}{e ^{\frac{x}{3}} + e ^{\frac{x}{6}}} d x

\frac{d}{d x} (7 e^{8 x})

What is the derivative of (sqrt(3x-1)/((2-x)^2)) ?
The derivative of (sqrt(3x-1)/((2-x)^2)) is -(9x+2)/(2(x-2)^3sqrt(3x-1))
What is the first derivative of (sqrt(3x-1)/((2-x)^2)) ?
The first derivative of (sqrt(3x-1)/((2-x)^2)) is -(9x+2)/(2(x-2)^3sqrt(3x-1))