What is the derivative of x^2\sqrt[4]{4x-7} ?

The derivative of x^2\sqrt[4]{4x-7} is 2x\sqrt[4]{4x-7}+(x^2)/((4x-7)^{3/4)}

What is the first derivative of x^2\sqrt[4]{4x-7} ?

The first derivative of x^2\sqrt[4]{4x-7} is 2x\sqrt[4]{4x-7}+(x^2)/((4x-7)^{3/4)}

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derivative of

Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d}{d x} (x^{2}) = 2 x

\frac{1}{( 4 x - 7 ) ^{\frac{3}{4}}} x^{2} = \frac{x ^{2}}{( 4 x - 7 ) ^{\frac{3}{4}}}

\frac{\partial}{\partial x} (x cos (x^{2} y))

\frac{d}{d y} (y^{3} + k x y^{4} - 2 x)

\int \frac{1}{x ^{2}} sin (\frac{1}{x}) cos (\frac{1}{x}) d x

\int_{0}^{3} x f (x^{2}) d x

\int_{0}^{2} 4 x^{2} - 2 x^{3} d x

What is the derivative of x^2\sqrt[4]{4x-7} ?
The derivative of x^2\sqrt[4]{4x-7} is 2x\sqrt[4]{4x-7}+(x^2)/((4x-7)^{3/4)}
What is the first derivative of x^2\sqrt[4]{4x-7} ?
The first derivative of x^2\sqrt[4]{4x-7} is 2x\sqrt[4]{4x-7}+(x^2)/((4x-7)^{3/4)}