What is the integral from 0 to 2 of 4x^2-2x^3 ?

The integral from 0 to 2 of 4x^2-2x^3 is 8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of 4x^2-2x^3

\int_{0}^{2} 4 x^{2} - 2 x^{3} d x

\frac{8}{3}

Decimal Notation

2.66666 \dots

Solution steps

\int_{0}^{2} 4 x^{2} - 2 x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 4 x^{2} d x - \int_{0}^{2} 2 x^{3} d x

\int_{0}^{2} 4 x^{2} d x = \frac{32}{3}

\int_{0}^{2} 2 x^{3} d x = 8

= \frac{32}{3} - 8

Simplify

\frac{32}{3} - 8 : \frac{8}{3}

= \frac{8}{3}

\frac{d}{d x} (x (x - 3)^{2})

y = x^{2}, y = - x^{2} + 4 x

\int 12 sin^{6} (x) cos^{3} (x) d x

f (x) = x^{\frac{5}{11}} (x - 5)^{2}

\frac{\partial}{\partial x} (\frac{3 x + 2 y}{y ^{2} + 5 x ^{2}})

What is the integral from 0 to 2 of 4x^2-2x^3 ?
The integral from 0 to 2 of 4x^2-2x^3 is 8/3