What is (\partial)/(\partial y)(x^4-x^2y) ?

The answer to (\partial)/(\partial y)(x^4-x^2y) is -x^2

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(\partial)/(\partial y)(x^4-x^2y)

\frac{\partial}{\partial y} (x^{4} - x^{2} y)

- x^{2}

Solution steps

\frac{\partial}{\partial y} (x^{4} - x^{2} y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{4}) - \frac{\partial}{\partial y} (x^{2} y)

\frac{\partial}{\partial y} (x^{4}) = 0

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

= 0 - x^{2}

Simplify

= - x^{2}

\int_{- 1}^{2} (x^{3} - x + 2) d x

\frac{d}{d x} ((10 - 5 x)^{4})

f (x) = (cot (x))^{4}

g (u) = (\frac{u ^{3} - 1}{u ^{3} + 1})^{8}

\frac{\partial}{\partial v} (uv)

What is (\partial)/(\partial y)(x^4-x^2y) ?
The answer to (\partial)/(\partial y)(x^4-x^2y) is -x^2