What is the sum from n=2 to infinity of (n+2)/(2n+3) ?

The sum from n=2 to infinity of (n+2)/(2n+3) is diverges

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sum from n=2 to infinity of (n+2)/(2n+3)

n = 2 \sum \infty \frac{n + 2}{2 n + 3}

diverges

Solution steps

n = 2 \sum \infty \frac{n + 2}{2 n + 3}

Apply Series Divergence Test:

diverges

= diverges

x \to 1 lim (x (2))

\frac{d}{d x} (a x^{2} + b y (x)^{2} + λ (x^{2} + y^{2} - c^{2}))

x^{2} - 2 x y + x y^{^{'}} = 0

\int \frac{x + 4}{x ^{2} + 5 x + 4} d x

x \to 3 + lim (ln (x^{2} - 9))

What is the sum from n=2 to infinity of (n+2)/(2n+3) ?
The sum from n=2 to infinity of (n+2)/(2n+3) is diverges