What is the integral from 0 to 5 of v(t) ?

The integral from 0 to 5 of v(t) is (25v)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 5 of v(t)

\int_{0}^{5} v (t) d t

\frac{25 v}{2}

Solution steps

\int_{0}^{5} v t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= v \cdot \int_{0}^{5} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{0}^{5}

= v [\frac{t ^{2}}{2}]_{0}^{5}

Compute the boundaries:

\frac{25}{2}

= v \frac{25}{2}

Simplify

= \frac{25 v}{2}

\frac{\partial}{\partial x} ((x y + 2) e^{- x y})

\frac{d}{d x} (- 4 sin (x) cos (x))

\int \frac{3}{x + 4} d x

f (x) = x^{3} + x, at x = 2

cos (sin^{2} (x - 2))

What is the integral from 0 to 5 of v(t) ?
The integral from 0 to 5 of v(t) is (25v)/2