What is the tangent of f(x)=6x^2+2x-7 ?

The tangent of f(x)=6x^2+2x-7 is y=(12a_{0}+2)x-6a_{0}^2-7

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tangent of f(x)=6x^2+2x-7

tangent of

f (x) = 6 x^{2} + 2 x - 7

y = (12 a_{0} + 2) x - 6 a_{0}^{2} - 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 a_{0}^{2} + 2 a_{0} - 7)

Find the slope of

f (x) = 6 x^{2} + 2 x - 7 : \frac{df ( x )}{d x} = 12 x + 2

Compute the slope of

f (x) = 6 x^{2} + 2 x - 7

x = a_{0} : m = 12 a_{0} + 2

Find the line with slope m=

12 a_{0} + 2

and passing through

(a_{0}, 6 a_{0}^{2} + 2 a_{0} - 7) : y = (12 a_{0} + 2) x - 6 a_{0}^{2} - 7

y = (12 a_{0} + 2) x - 6 a_{0}^{2} - 7

\int_{0}^{16} x e^{- x} d x

x \to 0 - lim (\frac{11}{tan ( x )})

\int 8 x ln (x) d x

\int \frac{( 2 x - 4 )}{( x - 2 ) ^{2}} d x

\frac{d y}{d x} = e^{- 2 x}

What is the tangent of f(x)=6x^2+2x-7 ?
The tangent of f(x)=6x^2+2x-7 is y=(12a_{0}+2)x-6a_{0}^2-7