What is the first d/(dt)(-cos(t)) ?

The first d/(dt)(-cos(t)) is sin(t)

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d/(dt)(-cos(t))

\frac{d}{d t} (- cos (t))

sin (t)

Solution steps

\frac{d}{d t} (- cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= - (- sin (t))

Simplify

= sin (t)

\int_{- 2}^{3} (x^{3} - 4 x) d x

x + 2, x^{2}, 0

9 x

\frac{\partial ^{2}}{\partial t ^{2}} (ln (3 x + 3 c t))

e^{y} y^{^{'}} = \frac{sin ( x )}{cos ^{2} ( x )}