What is the solution for e^yy^'=(sin(x))/(cos^2(x)) ?

The solution for e^yy^'=(sin(x))/(cos^2(x)) is y=ln(sec(x)+c_{1})

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e^yy^'=(sin(x))/(cos^2(x))

e^{y} y^{^{'}} = \frac{sin ( x )}{cos ^{2} ( x )}

y = ln (sec (x) + c_{1})

Solution steps

e^{y} y^{'} (x) = \frac{sin ( x )}{cos ^{2} ( x )}

Solve separable ODE:

y = ln (sec (x) + c_{1})

y = ln (sec (x) + c_{1})

\frac{d}{d x} (e^{s i n (x^{2})})

y^{^{'}} - 7 y = sin (2 x)

y = 1 + x - 4 x^{\frac{1}{2}}

arctan (\frac{1 + x}{1 - x})

2 + \frac{d y}{d x} = 2 x + y

What is the solution for e^yy^'=(sin(x))/(cos^2(x)) ?
The solution for e^yy^'=(sin(x))/(cos^2(x)) is y=ln(sec(x)+c_{1})