What is (\partial)/(\partial x)(-7(x+2y)^5) ?

The answer to (\partial)/(\partial x)(-7(x+2y)^5) is -35(x+2y)^4

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(\partial)/(\partial x)(-7(x+2y)^5)

\frac{\partial}{\partial x} (- 7 (x + 2 y)^{5})

- 35 (x + 2 y)^{4}

Solution steps

\frac{\partial}{\partial x} (- 7 (x + 2 y)^{5})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 7 \frac{\partial}{\partial x} ((x + 2 y)^{5})

Apply the chain rule:

5 (x + 2 y)^{4} \frac{\partial}{\partial x} (x + 2 y)

= 5 (x + 2 y)^{4} \frac{\partial}{\partial x} (x + 2 y)

\frac{\partial}{\partial x} (x + 2 y) = 1

= - 7 \cdot 5 (x + 2 y)^{4} \cdot 1

Simplify

= - 35 (x + 2 y)^{4}

\int \frac{1}{y ^{\frac{2}{3}}} d y

\frac{d ^{2}}{d x ^{2}} (\frac{2}{1 + x ^{2}})

\frac{d}{d x} (- x + 1)

\int π^{x} - x^{- 1} d x

\int_{7}^{14} - 30 x^{2} + 340 x d x

What is (\partial)/(\partial x)(-7(x+2y)^5) ?
The answer to (\partial)/(\partial x)(-7(x+2y)^5) is -35(x+2y)^4