What is the solution for (dy)/(dx)+cos(x)=(y+sin(x))^2 ?

The solution for (dy)/(dx)+cos(x)=(y+sin(x))^2 is y=-1/(x+c_{1)}-sin(x)

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(dy)/(dx)+cos(x)=(y+sin(x))^2

\frac{d y}{d x} + cos (x) = (y + sin (x))^{2}

y = - \frac{1}{x + c _{1}} - sin (x)

Solution steps

\frac{d y}{d x} + cos (x) = (y + sin (x))^{2}

Solve using substitution:

y = - \frac{1}{x + c _{1}} - sin (x)

y = - \frac{1}{x + c _{1}} - sin (x)

f (x) = sin (2 x) cos (2 x)

\frac{4 x}{x + 1}

\int e^{- 5 x} sin (4 x) d x

\frac{d y}{d x} = \frac{x}{y}, y (0) = - 4

x^{2} y^{^{''}} - 3 x y^{^{'}} + 4 y = 0

What is the solution for (dy)/(dx)+cos(x)=(y+sin(x))^2 ?
The solution for (dy)/(dx)+cos(x)=(y+sin(x))^2 is y=-1/(x+c_{1)}-sin(x)