What is the solution for (dy)/(dx)= x/y ,y(0)=-4 ?

The solution for (dy)/(dx)= x/y ,y(0)=-4 is y=-sqrt(x^2+16)

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(dy)/(dx)= x/y ,y(0)=-4

\frac{d y}{d x} = \frac{x}{y}, y (0) = - 4

y = - x^{2} + 16

Solution steps

\frac{d y}{d x} = \frac{x}{y}

Solve separable ODE:

y = - x^{2} + 16

y = - x^{2} + 16

x^{2} y^{^{''}} - 3 x y^{^{'}} + 4 y = 0

ln (x), x = 4

y^{^{''}} + y = sin (x), y (0) = 1, y (\frac{π}{2}) = 0

x^{7} (1 - \frac{2}{x + 4})

\frac{d}{d x} ((2 x - 6)^{4} (x^{2} + x + 1)^{5})

What is the solution for (dy)/(dx)= x/y ,y(0)=-4 ?
The solution for (dy)/(dx)= x/y ,y(0)=-4 is y=-sqrt(x^2+16)