What is the solution for y^{''}+y=sin(x),y(0)=1,y(pi/2)=0 ?

The solution for y^{''}+y=sin(x),y(0)=1,y(pi/2)=0 is y=-(xcos(x))/2+cos(x)

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y^{''}+y=sin(x),y(0)=1,y(pi/2)=0

y^{^{''}} + y = sin (x), y (0) = 1, y (\frac{π}{2}) = 0

y = - \frac{x cos ( x )}{2} + cos (x)

Solution steps

y^{''} (x) + y = sin (x)

Solve linear ODE:

y = - \frac{x cos ( x )}{2} + cos (x)

y = - \frac{x cos ( x )}{2} + cos (x)

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What is the solution for y^{''}+y=sin(x),y(0)=1,y(pi/2)=0 ?
The solution for y^{''}+y=sin(x),y(0)=1,y(pi/2)=0 is y=-(xcos(x))/2+cos(x)