What is the integral of sin(3pix) ?

The integral of sin(3pix) is -1/(3pi)cos(3pix)+C

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integral of sin(3pix)

\int sin (3 π x) d x

- \frac{1}{3 π} cos (3 π x) + C

Solution steps

\int sin (3 π x) d x

Apply u-substitution

: \int sin (u) \frac{1}{3 π} d u

= \int sin (u) \frac{1}{3 π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3 π} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{3 π} (- cos (u))

Substitute back

u = 3 π x

= \frac{1}{3 π} (- cos (3 π x))

Simplify

= - \frac{1}{3 π} cos (3 π x)

Add a constant to the solution

= - \frac{1}{3 π} cos (3 π x) + C

n = 0 \sum \infty 8^{n}

\frac{d}{d x} (\frac{2}{( 5 x + 1 ) ^{3}})

\int 96 - 32 t d t

y^{^{'}} = x e^{6}

What is the integral of sin(3pix) ?
The integral of sin(3pix) is -1/(3pi)cos(3pix)+C