What is (\partial)/(\partial x)(9x^7y^6+7x^5y^8) ?

The answer to (\partial)/(\partial x)(9x^7y^6+7x^5y^8) is 63y^6x^6+35y^8x^4

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(\partial)/(\partial x)(9x^7y^6+7x^5y^8)

\frac{\partial}{\partial x} (9 x^{7} y^{6} + 7 x^{5} y^{8})

63 y^{6} x^{6} + 35 y^{8} x^{4}

Solution steps

\frac{\partial}{\partial x} (9 x^{7} y^{6} + 7 x^{5} y^{8})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 x^{7} y^{6}) + \frac{\partial}{\partial x} (7 x^{5} y^{8})

\frac{\partial}{\partial x} (9 x^{7} y^{6}) = 63 y^{6} x^{6}

\frac{\partial}{\partial x} (7 x^{5} y^{8}) = 35 y^{8} x^{4}

= 63 y^{6} x^{6} + 35 y^{8} x^{4}

(3 x - 4)^{2}

f (x) = \frac{5}{1 + x ^{2}}

n = 1 \sum \infty n e^{- 4 n}

y = x^{4} + 9 x^{2} - x

\int \frac{1}{2} sec^{2} (5 x) d x

What is (\partial)/(\partial x)(9x^7y^6+7x^5y^8) ?
The answer to (\partial)/(\partial x)(9x^7y^6+7x^5y^8) is 63y^6x^6+35y^8x^4