What is the derivative of 3x+e^x ?

The derivative of 3x+e^x is 3+e^x

What is the first derivative of 3x+e^x ?

The first derivative of 3x+e^x is 3+e^x

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\frac{d}{d x} (3 x + e^{x})

3 + e^{x}

Solution steps

\frac{d}{d x} (3 x + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (e^{x}) = e^{x}

= 3 + e^{x}

\frac{\partial}{\partial y} (4 - x^{2} - 7 y^{2})

2 y^{^{''}} + 3 y^{^{'}} + y = t^{2} + 2 sin (t)

\frac{d}{d x} (arcsin (\frac{2}{x}))

(x^{2} + y + y^{2}) d x - x d y = 0

\int \frac{7}{x ^{2} + 3 x - 10} d x

What is the derivative of 3x+e^x ?
The derivative of 3x+e^x is 3+e^x
What is the first derivative of 3x+e^x ?
The first derivative of 3x+e^x is 3+e^x