What is the d/(dt)(sqrt(2)cos(t)-sqrt(2)) ?

The d/(dt)(sqrt(2)cos(t)-sqrt(2)) is -sqrt(2)sin(t)

What is the first d/(dt)(sqrt(2)cos(t)-sqrt(2)) ?

The first d/(dt)(sqrt(2)cos(t)-sqrt(2)) is -sqrt(2)sin(t)

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\frac{d}{d t} (2 cos (t) - 2)

- 2 sin (t)

Solution steps

\frac{d}{d t} (2 cos (t) - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 cos (t)) - \frac{d}{d t} (2)

\frac{d}{d t} (2 cos (t)) = - 2 sin (t)

\frac{d}{d t} (2) = 0

= - 2 sin (t) - 0

Simplify

= - 2 sin (t)

\int \frac{1}{1 + x + x ^{2}} d x

\int y^{- 3} d y

\frac{\partial}{\partial y} (x y^{2} arctan (z))

(4 x + 2 y) d x + (2 x + 2 y) d y = 0

x^{2} + y^{2} = 1, y = 1 - x

What is the d/(dt)(sqrt(2)cos(t)-sqrt(2)) ?
The d/(dt)(sqrt(2)cos(t)-sqrt(2)) is -sqrt(2)sin(t)
What is the first d/(dt)(sqrt(2)cos(t)-sqrt(2)) ?
The first d/(dt)(sqrt(2)cos(t)-sqrt(2)) is -sqrt(2)sin(t)