What is the solution for (4x+2y)dx+(2x+2y)dy=0 ?

The solution for (4x+2y)dx+(2x+2y)dy=0 is y=-x+sqrt(-x^2+c_{1)},y=-x-sqrt(-x^2+c_{1)}

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(4x+2y)dx+(2x+2y)dy=0

(4 x + 2 y) d x + (2 x + 2 y) d y = 0

y = - x + - x^{2} + c_{1}, y = - x - - x^{2} + c_{1}

Solution steps

(4 x + 2 y) d x + (2 x + 2 y) d y = 0

Solve exact ODE:

y = - x + - x^{2} + c_{1}, y = - x - - x^{2} + c_{1}

y = - x + - x^{2} + c_{1}, y = - x - - x^{2} + c_{1}

x^{2} + y^{2} = 1, y = 1 - x

n = 1 \sum \infty \frac{3}{n ^{3}}

y = \frac{9}{x - 2}, (3, 9)

\int_{- 2}^{2} (- x^{2} + 4) d x

2 y^{^{''}} - 6 y^{^{'}} + y = 0

What is the solution for (4x+2y)dx+(2x+2y)dy=0 ?
The solution for (4x+2y)dx+(2x+2y)dy=0 is y=-x+sqrt(-x^2+c_{1)},y=-x-sqrt(-x^2+c_{1)}