What is the tangent of y= 9/(sqrt(x-2)),(3,9) ?

The tangent of y= 9/(sqrt(x-2)),(3,9) is y=-9/2 x+45/2

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tangent of y= 9/(sqrt(x-2)),(3,9)

tangent of

y = \frac{9}{x - 2}, (3, 9)

y = - \frac{9}{2} x + \frac{45}{2}

Solution steps

Find the slope of

y = \frac{9}{x - 2} : \frac{d y}{d x} = - \frac{9}{2 ( x - 2 ) ^{\frac{3}{2}}}

Compute the slope of

y = \frac{9}{x - 2}

(3, 9) : m = - \frac{9}{2}

Find the line with slope m=

- \frac{9}{2}

and passing through

(3, 9) : y = - \frac{9}{2} x + \frac{45}{2}

y = - \frac{9}{2} x + \frac{45}{2}

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What is the tangent of y= 9/(sqrt(x-2)),(3,9) ?
The tangent of y= 9/(sqrt(x-2)),(3,9) is y=-9/2 x+45/2