What is the integral of 5sec^2(x) ?

The integral of 5sec^2(x) is 5tan(x)+C

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integral of 5sec^2(x)

\int 5 sec^{2} (x) d x

5 tan (x) + C

Solution steps

\int 5 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 5 tan (x)

Add a constant to the solution

= 5 tan (x) + C

6 x^{2} y^{^{'}} = y^{^{'}} + 6 x e^{- y}

\int \frac{2 x + 1}{x ^{2} + 2 x + 10} d x

x \to 2 lim (x^{2} - 3 x + 1)

x \to 2 lim ([1 + f (x)]^{2})

\frac{\partial}{\partial x} (\frac{2 x}{z - y})