What is (\partial)/(\partial x)((2x)/(z-y)) ?

The answer to (\partial)/(\partial x)((2x)/(z-y)) is 2/(z-y)

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(\partial)/(\partial x)((2x)/(z-y))

\frac{\partial}{\partial x} (\frac{2 x}{z - y})

\frac{2}{z - y}

Solution steps

\frac{\partial}{\partial x} (\frac{2 x}{z - y})

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{z - y} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= \frac{2}{z - y} \cdot 1

Simplify

= \frac{2}{z - y}

\int_{0}^{\frac{π}{3}} 10 sec^{2} (x) d x

\int_{- 7}^{7} 49 - x^{2} d x

- \frac{2}{5} x^{\frac{3}{4}}

\int_{1}^{6} \frac{5}{x ^{2}} d x

f (x) = x^{4} - 6 x^{2} + 9

What is (\partial)/(\partial x)((2x)/(z-y)) ?
The answer to (\partial)/(\partial x)((2x)/(z-y)) is 2/(z-y)