What is the integral from 1 to 6 of 5/(x^2) ?

The integral from 1 to 6 of 5/(x^2) is 25/6

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integral from 1 to 6 of 5/(x^2)

\int_{1}^{6} \frac{5}{x ^{2}} d x

\frac{25}{6}

Decimal Notation

4.16666 \dots

Solution steps

\int_{1}^{6} \frac{5}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{1}^{6} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{6}

= 5 [- \frac{1}{x}]_{1}^{6}

Compute the boundaries:

\frac{5}{6}

= 5 \cdot \frac{5}{6}

Simplify

= \frac{25}{6}

f (x) = x^{4} - 6 x^{2} + 9

\frac{d}{d t} (in cos (t))

\int x^{4} 5^{x} d x

f (x) = (x^{2} - 48)^{4}, at x = 7

\frac{d}{d x} (\frac{x}{3 x + 4 ln ( x )})

What is the integral from 1 to 6 of 5/(x^2) ?
The integral from 1 to 6 of 5/(x^2) is 25/6