What is the integral of 1/(2x+5) ?

The integral of 1/(2x+5) is 1/2 ln|2x+5|+C

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integral of 1/(2x+5)

\int \frac{1}{2 x + 5} d x

\frac{1}{2} ln ∣ 2 x + 5 ∣ + C

Solution steps

\int \frac{1}{2 x + 5} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = 2 x + 5

= \frac{1}{2} ln ∣ 2 x + 5 ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ 2 x + 5 ∣ + C

x \to 0 lim (x + 3)

\frac{d}{d x} (i e^{i x})

f^{^{'}} (t) = 0

\frac{d}{d x} ((x - 1)^{3})

\frac{d}{d x} (e^{(- 0.5 x)})