What is the integral from-2 to 0 of sqrt(x+2) ?

The integral from-2 to 0 of sqrt(x+2) is (4sqrt(2))/3

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integral from-2 to 0 of sqrt(x+2)

\int_{- 2}^{0} x + 2 d x

\frac{4 2}{3}

Decimal Notation

1.88561 \dots

Solution steps

\int_{- 2}^{0} x + 2 d x

Apply u-substitution

: \int_{0}^{2} u d u

= \int_{0}^{2} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{2}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{2}

Compute the boundaries:

\frac{4 2}{3}

= \frac{4 2}{3}

\int \frac{t}{( t ^{2} + 1 ) ^{\frac{23}{2}}} d t

\int 6 ln (x) d x

2 x^{3} + 9 x^{2} + 9 x + 6

n = 0 \sum \infty \frac{1}{( 0.5 ) ^{n}}

x = 2 y, x = y^{2} - 15

What is the integral from-2 to 0 of sqrt(x+2) ?
The integral from-2 to 0 of sqrt(x+2) is (4sqrt(2))/3