What is the integral of 6ln(x) ?

The integral of 6ln(x) is 6(xln(x)-x)+C

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integral of 6ln(x)

\int 6 ln (x) d x

6 (x ln (x) - x) + C

Solution steps

\int 6 ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int ln (x) d x

Apply Integration By Parts

: x ln (x) - \int 1 d x

= 6 (x ln (x) - \int 1 d x)

\int 1 d x = x

= 6 (x ln (x) - x)

Add a constant to the solution

= 6 (x ln (x) - x) + C

2 x^{3} + 9 x^{2} + 9 x + 6

n = 0 \sum \infty \frac{1}{( 0.5 ) ^{n}}

x = 2 y, x = y^{2} - 15

x \to 0 lim (\frac{( 3 + x ) ^{3} - 9}{x})

\frac{\partial}{\partial x} (z ln (x))