What is the limit as x approaches 0 of ((3+x)^3-9)/x ?

The limit as x approaches 0 of ((3+x)^3-9)/x is diverges

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limit as x approaches 0 of ((3+x)^3-9)/x

x \to 0 lim (\frac{( 3 + x ) ^{3} - 9}{x})

diverges

Solution steps

x \to 0 lim (\frac{( 3 + x ) ^{3} - 9}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{( 3 + x ) ^{3} - 9}{x}) = \infty

x \to 0 - lim (\frac{( 3 + x ) ^{3} - 9}{x}) = - \infty

= diverges

\frac{\partial}{\partial x} (z ln (x))

\frac{d y}{d x} = y (x y^{6} - 1)

\int x^{2} e^{\frac{x}{6}} d x

\frac{\partial}{\partial x} (- x yz + 54)

3 e^{x^{2}}

What is the limit as x approaches 0 of ((3+x)^3-9)/x ?
The limit as x approaches 0 of ((3+x)^3-9)/x is diverges