What is (\partial)/(\partial x)(-xyz+54) ?

The answer to (\partial)/(\partial x)(-xyz+54) is -yz

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(\partial)/(\partial x)(-xyz+54)

\frac{\partial}{\partial x} (- x yz + 54)

- yz

Solution steps

\frac{\partial}{\partial x} (- x yz + 54)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x yz) + \frac{\partial}{\partial x} (54)

\frac{\partial}{\partial x} (x yz) = yz

\frac{\partial}{\partial x} (54) = 0

= - yz + 0

Simplify

= - yz

3 e^{x^{2}}

f (x) = \frac{1}{3} x^{3} - 14 x^{2} + 6 x + 1

\frac{d}{d x} (- x + \frac{8}{x} + 1)

y^{^{''}} + 10 y^{^{'}} + 24 y = 0

n = 1 \sum \infty 0.5

What is (\partial)/(\partial x)(-xyz+54) ?
The answer to (\partial)/(\partial x)(-xyz+54) is -yz