What is the integral of cos^3(ax+b) ?

The integral of cos^3(ax+b) is 1/a (sin(ax+b)-(sin^3(ax+b))/3)+C

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integral of cos^3(ax+b)

\int cos^{3} (a x + b) d x

\frac{1}{a} (sin (a x + b) - \frac{sin ^{3} ( a x + b )}{3}) + C

Solution steps

\int cos^{3} (a x + b) d x

Apply u-substitution

: \int \frac{cos ^{3} ( u )}{a} d u

= \int \frac{cos ^{3} ( u )}{a} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{a} \cdot \int cos^{3} (u) d u

Rewrite using trig identities

= \frac{1}{a} \cdot \int (1 - sin^{2} (u)) cos (u) d u

Apply u-substitution

: \int 1 - v^{2} d v

= \frac{1}{a} \cdot \int 1 - v^{2} d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{a} (\int 1 d v - \int v^{2} d v)

\int 1 d v = v

\int v^{2} d v = \frac{v ^{3}}{3}

= \frac{1}{a} (v - \frac{v ^{3}}{3})

Substitute back

= \frac{1}{a} (sin (a x + b) - \frac{sin ^{3} ( a x + b )}{3})

Add a constant to the solution

= \frac{1}{a} (sin (a x + b) - \frac{sin ^{3} ( a x + b )}{3}) + C

x \to \infty lim (e^{2})

\int \frac{x ^{2} - 1}{x + 1} d x

\frac{d}{d x} (\frac{x ^{2}}{x - 1})

\int cos (c x) d x

What is the integral of cos^3(ax+b) ?
The integral of cos^3(ax+b) is 1/a (sin(ax+b)-(sin^3(ax+b))/3)+C