What is the integral from 1 to 16 of 4/(sqrt(x)) ?

The integral from 1 to 16 of 4/(sqrt(x)) is 24

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 16 of 4/(sqrt(x))

\int_{1}^{16} \frac{4}{x} d x

24

Solution steps

\int_{1}^{16} \frac{4}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{16} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{1}^{16}

= 4 [2 x^{\frac{1}{2}}]_{1}^{16}

Apply radical rule:

= 4 [2 x]_{1}^{16}

Compute the boundaries:

6

= 4 \cdot 6

Simplify

= 24

x \to 0 lim (\frac{2 x}{x ^{2} - 5 x})

\frac{\partial}{\partial x} (4 x ln (x) y)

\int (2 x + y)^{8} d x

x \to 0 + lim ((x)^{- x^{2}})

\frac{d}{d s} (\frac{s}{s ^{2} + b ^{2}})

What is the integral from 1 to 16 of 4/(sqrt(x)) ?
The integral from 1 to 16 of 4/(sqrt(x)) is 24