What is the limit as x approaches 0+of (x)^{-x^2} ?

The limit as x approaches 0+of (x)^{-x^2} is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of (x)^{-x^2}

x \to 0 + lim ((x)^{- x^{2}})

1

Solution steps

x \to 0 + lim (x^{- x^{2}})

Apply exponent rules

= x \to 0 + lim (e^{- x^{2} l n (x)})

Apply the Limit Chain Rule:

1

= 1

\frac{d}{d s} (\frac{s}{s ^{2} + b ^{2}})

t e^{2 t}

y^{^{''}} + 5 y^{^{'}} + 4 y = sin (3 x)

\frac{\partial}{\partial x} (x y + x^{2})

9 (x^{2} + y^{2}) d x + 7 x y d y = 0

What is the limit as x approaches 0+of (x)^{-x^2} ?
The limit as x approaches 0+of (x)^{-x^2} is 1