What is the derivative of 400-3P+4T+0.6A ?

The derivative of 400-3P+4T+0.6A is -3

What is the first derivative of 400-3P+4T+0.6A ?

The first derivative of 400-3P+4T+0.6A is -3

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derivative of

400 - 3 P + 4 T + 0.6 A

- 3

Solution steps

\frac{d}{d P} (400 - 3 P + 4 T + 0.6 A)

Treat

T, A

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d P} (400) - \frac{d}{d P} (3 P) + \frac{d}{d P} (4 T) + \frac{d}{d P} (0.6 A)

\frac{d}{d P} (400) = 0

\frac{d}{d P} (3 P) = 3

\frac{d}{d P} (4 T) = 0

\frac{d}{d P} (0.6 A) = 0

= 0 - 3 + 0 + 0

Simplify

= - 3

\frac{d y}{d x} = \frac{- x}{y}

x \to \frac{5}{4} lim (\frac{16 x ^{2} - 25}{4 x - 5})

\frac{d}{d x} (1 - cos (x^{3}))

(t - 3)^{3}

\int_{0}^{2} \frac{x}{( 1 + 2 x ^{2} ) ^{2}} d x

What is the derivative of 400-3P+4T+0.6A ?
The derivative of 400-3P+4T+0.6A is -3
What is the first derivative of 400-3P+4T+0.6A ?
The first derivative of 400-3P+4T+0.6A is -3