What is the limit as x approaches 5/4 of (16x^2-25)/(4x-5) ?

The limit as x approaches 5/4 of (16x^2-25)/(4x-5) is 10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5/4 of (16x^2-25)/(4x-5)

x \to \frac{5}{4} lim (\frac{16 x ^{2} - 25}{4 x - 5})

10

Solution steps

x \to \frac{5}{4} lim (\frac{16 x ^{2} - 25}{4 x - 5})

Simplify

\frac{16 x ^{2} - 25}{4 x - 5} : 4 x + 5

= x \to \frac{5}{4} lim (4 x + 5)

Plug in the value

x = \frac{5}{4}

= 4 \cdot \frac{5}{4} + 5

Simplify

4 \cdot \frac{5}{4} + 5 : 10

= 10

\frac{d}{d x} (1 - cos (x^{3}))

(t - 3)^{3}

\int_{0}^{2} \frac{x}{( 1 + 2 x ^{2} ) ^{2}} d x

\int_{- 18}^{32} \frac{1}{2 x} d x

\frac{d ^{2}}{d x ^{2}} (x^{2} + 11)

What is the limit as x approaches 5/4 of (16x^2-25)/(4x-5) ?
The limit as x approaches 5/4 of (16x^2-25)/(4x-5) is 10