What is the integral from-18 to 32 of 1/(sqrt(2x)) ?

The integral from-18 to 32 of 1/(sqrt(2x)) is -Does not exist+8

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integral from-18 to 32 of 1/(sqrt(2x))

\int_{- 18}^{32} \frac{1}{2 x} d x

- Does not exist + 8

Solution steps

\int_{- 18}^{32} \frac{1}{2 x} d x

Adjust integral based on undefined pointsThere is an undefined point within the boundaries at

: 0

= \int_{- 18}^{0} \frac{1}{2 x} d x + \int_{0}^{32} \frac{1}{2 x} d x

\int_{- 18}^{0} \frac{1}{2 x} d x = -

Does not exist

= - Does not exist + \int_{0}^{32} \frac{1}{2 x} d x

\int_{0}^{32} \frac{1}{2 x} d x = 8

= - Does not exist + 8

\frac{d ^{2}}{d x ^{2}} (x^{2} + 11)

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y^{^{''}} + y = x

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What is the integral from-18 to 32 of 1/(sqrt(2x)) ?
The integral from-18 to 32 of 1/(sqrt(2x)) is -Does not exist+8