What is the tangent of f(x)=3x^2+3x,\at x=-2 ?

The tangent of f(x)=3x^2+3x,\at x=-2 is y=-9x-12

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tangent of f(x)=3x^2+3x,\at x=-2

tangent of

f (x) = 3 x^{2} + 3 x, at x = - 2

y = - 9 x - 12

Solution steps

Find the tangent point:

(- 2, 6)

Find the slope of

f (x) = 3 x^{2} + 3 x : \frac{df ( x )}{d x} = 6 x + 3

Compute the slope of

f (x) = 3 x^{2} + 3 x

x = - 2 : m = - 9

Find the line with slope m=

- 9

and passing through

(- 2, 6) : y = - 9 x - 12

y = - 9 x - 12

\int ∣ 5 x ∣ d x

f (x) = \frac{53}{0.01 x ^{2} + 1}

\int \frac{e ^{- 4 x}}{x ^{2}} d x

y = - x^{3} + 3, y = x, x = - 1, x = 1

y^{4} - 4 y^{2} = x^{4} - 9 x^{2}, (- 3, - 2)

What is the tangent of f(x)=3x^2+3x,\at x=-2 ?
The tangent of f(x)=3x^2+3x,\at x=-2 is y=-9x-12