What is the solution for y^'=((x^2+y^2))/(xy) ?

The solution for y^'=((x^2+y^2))/(xy) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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y^'=((x^2+y^2))/(xy)

y^{^{'}} = \frac{( x ^{2} + y ^{2} )}{x y}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{( x ^{2} + y ^{2} )}{x y}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

\frac{d}{d x} (14 x e^{- x})

x^{2} f (x^{2} + 2 x)

\frac{\partial}{\partial y} (3 x cos (y))

\int \frac{21}{x ( x ^{2} + 4 ) ^{2}} d x

\frac{d}{d x} (ln (\frac{( x + 2 )}{x ^{2}}))

What is the solution for y^'=((x^2+y^2))/(xy) ?
The solution for y^'=((x^2+y^2))/(xy) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}