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Popular >

area y=x^2-1,y=0,[0,3]

Solution

area

y = x^{2} - 1, y = 0, [0, 3]

Solution

\frac{22}{3}

+1

Decimal Notation

7.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{3} x^{2} - 1 d x

Solve

\int_{0}^{3} x^{2} - 1 d x : \frac{22}{3}

The area is:

= \frac{22}{3}

Popular Examples

derivative of f(x)= 1/4 x-1/6 derivative of

f (x) = \frac{1}{4} x - \frac{1}{6}

t y^{^{'}} + 9 y = 3 t

area 2/x ,2x,0,3 area

\frac{2}{x}, 2 x, 0, 3

(dy)/(dt)+3y=5,y(0)=1

\frac{d y}{d t} + 3 y = 5, y (0) = 1

y^{''}+16y=-24sin(4t)

y^{^{''}} + 16 y = - 24 sin (4 t)

Frequently Asked Questions (FAQ)

What is area y=x^2-1,y=0,[0,3] ?
The answer to area y=x^2-1,y=0,[0,3] is 22/3