What is the integral of (x^2e^{2x}) ?

The integral of (x^2e^{2x}) is 1/2 e^{2x}x^2-1/4 (e^{2x}*2x-e^{2x})+C

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integral of (x^2e^{2x})

\int (x^{2} e^{2 x}) d x

\frac{1}{2} e^{2 x} x^{2} - \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x}) + C

Solution steps

\int x^{2} e^{2 x} d x

Apply Integration By Parts

: \frac{1}{2} e^{2 x} x^{2} - \int e^{2 x} x d x

= \frac{1}{2} e^{2 x} x^{2} - \int e^{2 x} x d x

\int e^{2 x} x d x = \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x})

= \frac{1}{2} e^{2 x} x^{2} - \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x})

Add a constant to the solution

= \frac{1}{2} e^{2 x} x^{2} - \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x}) + C

x \to - \infty lim (f (x))

\frac{d}{d x} (4 x^{3} - 156 x^{2} + 1512 x)

\frac{d}{d x} (y e^{x^{2}})

6 cos (3 x)

\frac{d y}{d x} = x y^{2}

What is the integral of (x^2e^{2x}) ?
The integral of (x^2e^{2x}) is 1/2 e^{2x}x^2-1/4 (e^{2x}*2x-e^{2x})+C