What is the derivative of 7/(8t^4) ?

The derivative of 7/(8t^4) is -7/(2t^5)

What is the first derivative of 7/(8t^4) ?

The first derivative of 7/(8t^4) is -7/(2t^5)

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derivative of

\frac{7}{8 t ^{4}}

- \frac{7}{2 t ^{5}}

Solution steps

\frac{d}{d t} (\frac{7}{8 t ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{7}{8} \frac{d}{d t} (\frac{1}{t ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{7}{8} \frac{d}{d t} (t^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{7}{8} (- 4 t^{- 4 - 1})

Simplify

\frac{7}{8} (- 4 t^{- 4 - 1}) : - \frac{7}{2 t ^{5}}

= - \frac{7}{2 t ^{5}}

\frac{d}{d x} (x^{2} + c)

x \to 2 lim (\frac{2 + x}{2 - 4})

n = 0 \sum \infty 2 (\frac{1}{3 ^{n}})

\frac{d}{d z} (e^{z})

sin (2 x - 1)

What is the derivative of 7/(8t^4) ?
The derivative of 7/(8t^4) is -7/(2t^5)
What is the first derivative of 7/(8t^4) ?
The first derivative of 7/(8t^4) is -7/(2t^5)