What is the derivative of 3x^2-1/24 ln(x) ?

The derivative of 3x^2-1/24 ln(x) is 6x-1/(24x)

What is the first derivative of 3x^2-1/24 ln(x) ?

The first derivative of 3x^2-1/24 ln(x) is 6x-1/(24x)

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\frac{d}{d x} (3 x^{2} - \frac{1}{24} ln (x))

6 x - \frac{1}{24 x}

Solution steps

\frac{d}{d x} (3 x^{2} - \frac{1}{24} ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (\frac{1}{24} ln (x))

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{1}{24} ln (x)) = \frac{1}{24 x}

= 6 x - \frac{1}{24 x}

\int \frac{1}{x ^{2} + 4 x + 20} d x

x \to 1 lim (e^{x})

x \to 5 lim (x^{- 1})

\frac{d}{d x} (2 x - 4 sin (x))

A x^{n} + B e^{x}

What is the derivative of 3x^2-1/24 ln(x) ?
The derivative of 3x^2-1/24 ln(x) is 6x-1/(24x)
What is the first derivative of 3x^2-1/24 ln(x) ?
The first derivative of 3x^2-1/24 ln(x) is 6x-1/(24x)