What is the derivative of f(x)= 3/(\sqrt[4]{x)} ?

The derivative of f(x)= 3/(\sqrt[4]{x)} is -3/(4x^{5/4)}

What is the first derivative of f(x)= 3/(\sqrt[4]{x)} ?

The first derivative of f(x)= 3/(\sqrt[4]{x)} is -3/(4x^{5/4)}

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derivative of

- \frac{3}{4 x ^{\frac{5}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} (x^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- \frac{1}{4} x^{- \frac{1}{4} - 1})

Simplify

3 (- \frac{1}{4} x^{- \frac{1}{4} - 1}) : - \frac{3}{4 x ^{\frac{5}{4}}}

= - \frac{3}{4 x ^{\frac{5}{4}}}

f (x) = x, at x = 16.3

arcsin (x)

\frac{d ^{2}}{d x ^{2}} (2 x cos (x^{2}))

\int_{8}^{14} \frac{y}{y ^{2} - 4 y - 5} d y

y^{^{'}} = e^{- 2 x}

What is the derivative of f(x)= 3/(\sqrt[4]{x)} ?
The derivative of f(x)= 3/(\sqrt[4]{x)} is -3/(4x^{5/4)}
What is the first derivative of f(x)= 3/(\sqrt[4]{x)} ?
The first derivative of f(x)= 3/(\sqrt[4]{x)} is -3/(4x^{5/4)}