What is the integral from 0 to pi/3 of 7sec^2(x) ?

The integral from 0 to pi/3 of 7sec^2(x) is 7sqrt(3)

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integral from 0 to pi/3 of 7sec^2(x)

\int_{0}^{\frac{π}{3}} 7 sec^{2} (x) d x

73

Decimal Notation

12.12435 \dots

Solution steps

\int_{0}^{\frac{π}{3}} 7 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{0}^{\frac{π}{3}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 7 [tan (x)]_{0}^{\frac{π}{3}}

Compute the boundaries:

3

= 73

\frac{d}{d x} (cos (x) \cdot sin (y))

\frac{\partial}{\partial x} (3 ln (x))

(x + 6), x, - 2, 3

\int sec^{6} (x) tan (x) d x

y = 2 3^{x}

What is the integral from 0 to pi/3 of 7sec^2(x) ?
The integral from 0 to pi/3 of 7sec^2(x) is 7sqrt(3)