What is the integral of sec^6(x)tan(x) ?

The integral of sec^6(x)tan(x) is (sec^6(x))/6+C

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integral of sec^6(x)tan(x)

\int sec^{6} (x) tan (x) d x

\frac{sec ^{6} ( x )}{6} + C

Solution steps

\int sec^{6} (x) tan (x) d x

Apply u-substitution

: \int u^{5} d u

= \int u^{5} d u

Apply the Power Rule

: \frac{u ^{6}}{6}

= \frac{u ^{6}}{6}

Substitute back

u = sec (x)

= \frac{sec ^{6} ( x )}{6}

Add a constant to the solution

= \frac{sec ^{6} ( x )}{6} + C

y = 2 3^{x}

y = ln (7 x)

\frac{d}{d x} (e^{x^{3} + 3 x})

x \to 2 lim (\frac{∣ x - 2 ∣}{2})

10 (1.05)^{x}

What is the integral of sec^6(x)tan(x) ?
The integral of sec^6(x)tan(x) is (sec^6(x))/6+C