What is (\partial)/(\partial z)(cos(xyz)) ?

The answer to (\partial)/(\partial z)(cos(xyz)) is -sin(xyz)xy

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(\partial)/(\partial z)(cos(xyz))

\frac{\partial}{\partial z} (cos (x yz))

- sin (x yz) x y

Solution steps

\frac{\partial}{\partial z} (cos (x yz))

Treat

x, y

as constants

Apply the chain rule:

- sin (x yz) \frac{\partial}{\partial z} (x yz)

= - sin (x yz) \frac{\partial}{\partial z} (x yz)

\frac{\partial}{\partial z} (x yz) = x y

= - sin (x yz) x y

\frac{d y}{d t} = 1.4 y

\int \frac{1}{- x ^{2} - 1} d x

y^{^{'}} = \frac{( x y ^{3} )}{25}

\frac{d y}{d x} = \frac{6 y}{x ^{2}}

What is (\partial)/(\partial z)(cos(xyz)) ?
The answer to (\partial)/(\partial z)(cos(xyz)) is -sin(xyz)xy