What is the solution for y^'=((xy^3))/(25) ?

The solution for y^'=((xy^3))/(25) is y=sqrt(-(25)/(x^2+c_{1))},y=-sqrt(-(25)/(x^2+c_{1))}

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y^'=((xy^3))/(25)

y^{^{'}} = \frac{( x y ^{3} )}{25}

y = - \frac{25}{x ^{2} + c _{1}}, y = - - \frac{25}{x ^{2} + c _{1}}

Solution steps

y^{'} (x) = \frac{( x y ^{3} )}{25}

Solve separable ODE:

y = - \frac{25}{x ^{2} + c _{1}}, y = - - \frac{25}{x ^{2} + c _{1}}

y = - \frac{25}{x ^{2} + c _{1}}, y = - - \frac{25}{x ^{2} + c _{1}}

\frac{d y}{d x} = \frac{6 y}{x ^{2}}

\int - 18 t + 4 d t

\int csc^{2} (x) + 5 d x

(1 - x)^{^{'}}

\frac{\partial}{\partial x} (- 2 x e^{- x^{2}})

What is the solution for y^'=((xy^3))/(25) ?
The solution for y^'=((xy^3))/(25) is y=sqrt(-(25)/(x^2+c_{1))},y=-sqrt(-(25)/(x^2+c_{1))}