What is the (sqrt(1-x))^' ?

The (sqrt(1-x))^' is -1/(2sqrt(1-x))

What is the first (sqrt(1-x))^' ?

The first (sqrt(1-x))^' is -1/(2sqrt(1-x))

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(1 - x)^{^{'}}

- \frac{1}{2 1 - x}

Solution steps

(1 - x)^{'}

Apply the chain rule:

\frac{1}{2 1 - x} (1 - x)^{'}

= \frac{1}{2 1 - x} (1 - x)^{'}

(1 - x)^{'} = - 1

= \frac{1}{2 1 - x} (- 1)

Simplify

= - \frac{1}{2 1 - x}

\frac{\partial}{\partial x} (- 2 x e^{- x^{2}})

16 y^{^{''}} - 40 y^{^{'}} + 25 y = 0

sec^{2} (x)

2 y^{^{''}} + 17 y^{^{'}} - 9 y = 0

\frac{d}{d y} (x y + y z + x z)