What is the derivative of (x^3-1/(x-1)) ?

The derivative of (x^3-1/(x-1)) is 2x+1

What is the first derivative of (x^3-1/(x-1)) ?

The first derivative of (x^3-1/(x-1)) is 2x+1

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Popular >

\frac{d}{d x} (\frac{x ^{3} - 1}{x - 1})

2 x + 1

Solution steps

\frac{d}{d x} (\frac{x ^{3} - 1}{x - 1})

Simplify

\frac{x ^{3} - 1}{x - 1} : x^{2} + x + 1

= \frac{d}{d x} (x^{2} + x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 2 x + 1 + 0

Simplify

= 2 x + 1

\frac{\partial}{\partial x} (ln (10 x))

\frac{d}{d x} (\frac{x}{lo g _{e} ( x )})

\frac{d}{d x} (b e^{- x})

\int (x^{\frac{3}{2}} + 2 x + 1) d x

h \to 0 lim (\frac{\frac{2}{1 + h} - 2}{h})

What is the derivative of (x^3-1/(x-1)) ?
The derivative of (x^3-1/(x-1)) is 2x+1
What is the first derivative of (x^3-1/(x-1)) ?
The first derivative of (x^3-1/(x-1)) is 2x+1