What is the sum from n=5 to infinity of (n^3)/(2^n) ?

The sum from n=5 to infinity of (n^3)/(2^n) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=5 to infinity of (n^3)/(2^n)

n = 5 \sum \infty \frac{n ^{3}}{2 ^{n}}

converges

Solution steps

n = 5 \sum \infty \frac{n ^{3}}{2 ^{n}}

Apply Series Ratio Test:

converges

= converges

f^{^{''}} (x) = 2

x \to - \infty lim (x + \frac{1}{x})

\int_{0}^{\frac{π}{4}} sec (x) d x

\int 24 x^{5} d x

\int 2 x ln (x) d x

What is the sum from n=5 to infinity of (n^3)/(2^n) ?
The sum from n=5 to infinity of (n^3)/(2^n) is converges