What is the integral from 0 to pi/4 of sec(x) ?

The integral from 0 to pi/4 of sec(x) is ln(1+sqrt(2))

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integral from 0 to pi/4 of sec(x)

\int_{0}^{\frac{π}{4}} sec (x) d x

ln (1 + 2)

Decimal Notation

0.88137 \dots

Solution steps

\int_{0}^{\frac{π}{4}} sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= [ln ∣ tan (x) + sec (x) ∣]_{0}^{\frac{π}{4}}

Compute the boundaries:

ln (1 + 2)

= ln (1 + 2)

\int 24 x^{5} d x

\int 2 x ln (x) d x

\frac{d}{d x} (cos (4 e^{- 8 x}))

f (x) = x + \frac{2}{x}, (2, 3)

\frac{1}{( 1 + x ^{2} ) ^{2}}

What is the integral from 0 to pi/4 of sec(x) ?
The integral from 0 to pi/4 of sec(x) is ln(1+sqrt(2))