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Popular >

area y=x^2+1,y=5

Solution

area

y = x^{2} + 1, y = 5

Solution

\frac{32}{3}

+1

Decimal Notation

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} - 4 d x

Solve

\int_{- 2}^{2} x^{2} - 4 d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Popular Examples

tangent of f(x)=7x^2-x^3,(1,6)tangent of

f (x) = 7 x^{2} - x^{3}, (1, 6)

integral of 18x^2-14x+9

\int 18 x^{2} - 14 x + 9 d x

tangent of x+2/x tangent of

x + \frac{2}{x}

t^2y^{''}-2ty^'+2y=3t^2

t^{2} y^{^{''}} - 2 t y^{^{'}} + 2 y = 3 t^{2}

integral from 1 to sqrt(3 of)arctan(1/x)

\int_{1}^{3} arctan (\frac{1}{x}) d x

Frequently Asked Questions (FAQ)

What is area y=x^2+1,y=5 ?
The answer to area y=x^2+1,y=5 is 32/3